Posted by **K** on Wednesday, April 3, 2013 at 1:40pm.

average for all football teams was an 86 with variance of 16. the buckeyes program over the last 16 year was a 93. is there sufficient proof at the .05 level of significance to say buckeyes were higher than everyone else.

- Stastics -
**MathGuru**, Wednesday, April 3, 2013 at 9:14pm
Use a one-sample z-test.

z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size)

Note: Standard deviation is the square root of the variance.

Check a z-table at .05 level of significance for a one-tailed test.

If the z-test statistic exceeds the critical value from the z-table, reject the null. If the z-test statistic does not exceed the critical value from the z-table, do not reject the null.

I'll let you take it from here.

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