Posted by K on Wednesday, April 3, 2013 at 1:40pm.
average for all football teams was an 86 with variance of 16. the buckeyes program over the last 16 year was a 93. is there sufficient proof at the .05 level of significance to say buckeyes were higher than everyone else.

Stastics  MathGuru, Wednesday, April 3, 2013 at 9:14pm
Use a onesample ztest.
z = (sample mean  population mean)/(standard deviation divided by the square root of the sample size)
Note: Standard deviation is the square root of the variance.
Check a ztable at .05 level of significance for a onetailed test.
If the ztest statistic exceeds the critical value from the ztable, reject the null. If the ztest statistic does not exceed the critical value from the ztable, do not reject the null.
I'll let you take it from here.
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