Posted by C on .
How would I find the confidence level (in %) if I am given the standard deviation, size of the random sample, and confidence interval?

Statistics 
MathGuru,
You would solve for the zvalue using the margin of error (derived from the confidence interval), standard deviation, and the sample size.
Margin of error = zvalue (sd/√n)
Once you have the zvalue, find the percentage using a ztable.