Posted by **C** on Wednesday, April 3, 2013 at 10:51am.

How would I find the confidence level (in %) if I am given the standard deviation, size of the random sample, and confidence interval?

- Statistics -
**MathGuru**, Wednesday, April 3, 2013 at 8:55pm
You would solve for the z-value using the margin of error (derived from the confidence interval), standard deviation, and the sample size.

Margin of error = z-value (sd/√n)

Once you have the z-value, find the percentage using a z-table.

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