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How would I find the confidence level (in %) if I am given the standard deviation, size of the random sample, and confidence interval?

  • Statistics - ,

    You would solve for the z-value using the margin of error (derived from the confidence interval), standard deviation, and the sample size.

    Margin of error = z-value (sd/√n)

    Once you have the z-value, find the percentage using a z-table.

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