Monday

April 21, 2014

April 21, 2014

Posted by **Jane** on Wednesday, April 3, 2013 at 9:50am.

Simplify each quotient

7/sq rt 2 - sq rt 3

Please solve and explain how you did it. What do you do when the denominator is a negative?

- Alg 1 -
**Steve**, Wednesday, April 3, 2013 at 11:10am7/(√2-√3)

since (a-b)(a+b) = a^2-b^2,

= 7/(√2-√3) * (√2+√3)/(√2+√3)

= 7(√2+√3)/(2-3)

= -7(√2+√3)

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