Wednesday

August 27, 2014

August 27, 2014

Posted by **Zoe** on Wednesday, April 3, 2013 at 12:28am.

I'm totally stuck...

- Math-Calculus -
**Steve**, Wednesday, April 3, 2013 at 12:07pmDraw a diagram. Label as P the point on the ocean directly above the pulley. If the ship being pulled is x meters from P, and the pulling ship is at distance y,

√(x^2+45^2) + √(y^2+45^2) = 200

3 km/hr = 50m/min, so we want

dx/dt when t=1 and dy/dt=50.

at t=0, x=y=89.30

after 1 minute, y=139.30, so x=29.14

x/√(x^2+45^2) dx/dt + y/√(y^2+45^2) dy/dt = 0

29.14/53.61 dx/dt + 139.30/146.39 * 50 = 0

dx/dt = -87.53 m/s = 5.25 km/hr

Note that this cannot continue for long, as the ship will be pulled under by the cable.

**Related Questions**

angle - 1.) From the top of a lighthouse 52 metres high,the angles of depression...

geometry - the pilot of a plane flying 2000 meters above sea level observes two ...

maths - An airplane is flying at an altitude of 10,000m. The pilot sees two ...

maths - Iam stuck with this question.Please anyone help me. An airplane is ...

Trigonometry - An observer in a lighthouse 350 feet above sea level observes two...

math - an observer in a lighthouse 300 ft above sea level observes 2 ships ...

geometry - Two ships leave a harbor at the same time, traveling on courses that ...

10th grade - Two ships leave a harbor at the same time, traveling on courses ...

trig - Help! Ships A and B leave port at the same time and sail on straight ...

physics - Ships A and B leave port together. For the next two hours, ship A ...