Friday
March 24, 2017

Post a New Question

Posted by on .

A constant torque of 22.9 N·m is applied to a grindstone whose moment of inertia is 0.168 kg·m2. Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 17.1 rev, assuming it started
from rest.
Answer in units of rev/s

  • Physics - ,

    M=Iε
    ε=M/I = 22.9/0.168 = 136.3 rad/s²
    2πN=2πn₀t + εt²/2
    2πn=2πn₀ + εt
    n₀=0 =>
    2πN= εt²/2
    2πn= εt => t=2πn/ε
    N= πn²/ε
    n=sqrt {εN/π}=
    =sqrt{136.3•17.1/3.14}=27.24 rev/s

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question