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April 1, 2015

April 1, 2015

Posted by **mani** on Tuesday, April 2, 2013 at 12:42pm.

- geometry -
**Steve**, Tuesday, April 2, 2013 at 1:35pmwe can without loss of generality let the line be the x-axis, and F be at (0,k+1).

We know that if the ratio is 1, the locus is a parabola. Maybe it still is.

If P starts at (0,1) the ratio is k. We have

y = √(x^2 + (k-y)^2)

y^2 = x^2 + y^2 - 2ky + k^2

2ky = x^2+k^2

it's still a parabola.

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