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April 18, 2014

April 18, 2014

Posted by **ALEX** on Tuesday, April 2, 2013 at 11:28am.

thank you

- advance functions gr12 HELP ASAP -
**Steve**, Tuesday, April 2, 2013 at 11:37amas with all fractions , cross-multiply to get rid of them:

(x+5)(x) = (2x+7)(x-3) assuming x≠0,3

x^2+5x = 2x^2+x-21

x^2-4x-21 = 0

(x-7)(x+3) = 0

x = -3,7

check:

(-3+5)/(-3-3) = -1/3 = (-6+7)/(-3)

(7+5)/(7-3) = 3 = (14+7)/7

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