physics...
posted by HELP ME...uRGENT! on .
A kayaker paddles due north at 2 m/s. The river the kayaker is paddling in flows towards the east at 1 m/s. After 5 seconds of paddling, how far is the kayaker from where she started in m?

v=sqrt(v₁²+v₂²) = sqrt(4+1) =2.236 m/s
s=vt=2.236•5=11.18 m