Posted by chris on .
The mean number of bumped airline passengers per day s 1.35 and the standard deviation is 0.25. For a random selection of a group of 40 days, what is the probability that the mean number of bumped passengers for the 40 days will be between 1.25 and 1.50?

stats. 
PsyDAG,
Z = (scoremean)/SEm
SEm = SD/√n
n = 40
Use same table.