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January 25, 2015

January 25, 2015

Posted by **Jeconiah** on Monday, April 1, 2013 at 11:10pm.

- Maths -
**Anonymous**, Monday, April 1, 2013 at 11:59pmfactor out an a

a(x^2 + b/a) + c = 0

compete the square and don't change the value

a(x^2 + b/a + b^2/4a^2) - a(b^2/4a^2) + c = 0

a(x + b/2a)^2 - b^2/4a + c = 0

(x + b/2a)^2 - b^2/4a^2 + c/a = 0

(x+b/2a)^2 = (b^2 - 4ac)/4a^2

x + b/2a = ±√(b^2-4ac) / 2a

x = (-b ± √(b^2-4ac))/2a

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