Math
posted by Jane on .
Pythagorean Theorem
A rectanglar box is 9 in. wide, 11 in. tall, and 20 in. long. What is the diameter of the smallest circular opening through which the box will fit? If necessary, round to the nearest tenth of a centimeter.

Try to put it through the circle using the smaller end
that is, the 9 by 11 end
We need the diameter of that rectangle
x^2 = 9^2 + 11^2 = 202
x = √202 = appr 14.2
so the circle will have to be > 14.2