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Physics - Electric Potential

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A charge of - 0.15 C is moved from a position where the electric potential is 13 V to a position where the electric potential is 60 V. What is the change in potential energy of the charge associated with this change in position?

  • Physics - Electric Potential - ,

    ΔPE= -Work=-qΔφ= -{(-0.15)•(13-60)} =
    =-7.05 J

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