Posted by Elizabeth on Sunday, March 31, 2013 at 6:18pm.
A baseball player hits a baseball into the air with an initial vertical velocity of 48 feet per second from a
height of 3 feet.
8. Write an equation that gives the baseball’s height as a function of the time (in seconds) after it is hit.
9. After how many seconds does the baseball reach its maximum height?
10. What is the maximum height?
Algebra - Reiny, Sunday, March 31, 2013 at 7:07pm
height = -16t^2 + 48t + 3
d(height)/dt = velocity = -32t + 48
= 0 at a max of height
32t = 48
t = 48/32 = 1.5
Maximum height is reached after 1.5 seconds
that height is
-16(1.5)^2 + 48(1.5) + 3 = 39 ft
If you don't know Calculus, then you have to find the vertex of the above parabola, usually by completing the square.
A short-cut would be to find the x of the vertex by
-b/(2a) = -48/(-32) = 1.5
then subbing in just like before to the actual maximum
Answer This Question
More Related Questions
- Algebra - A baseball is hit at a point 2 feet above the ground at a velocity of ...
- algebra - A baseball player releases a baseball at the height of 7 feet above ...
- Alegra 2 - A baseball is hit at a point of 3 feet above ground at a velocity of ...
- Math - A baseball is thrown up in the air from a height of 3 feet with an ...
- Algebra - A baseball player hits a foul ball straight up in the air from a ...
- Algebra 2 - A baseball player swings and hits a pop fly straight up in the air ...
- calculus - A baseball pitcher throws a baseball with an initial velocity of 133 ...
- math - A baseball player swings and hits a pop fly straight up in the air to the...
- Algebra - The path of a baseball after being hit is given by the function f(x...
- Pre-Cal - A baseball player throws baseball at a velocity 139ft per second at an...