Chemistry
posted by Sean on .
Determine the value of the equilibrium constant,Kgoal , for the reaction
N2(g)+O2(g)+H2(g)<=> (1/2)N2H4(g) + NO2(g)
Kgoal=?
by making use of the following information:
1.N2(g)+O2(g)<=>2NO(g), K1=4.1010x10^31
2.N2(g)+2H2(g)<=>N2H4(g), K2=7.40x10^26
3.2NO(g)+O2(g)<=>2NO2(g), K3=6.00x10^13
express your answer numerically:

Take 1/2 equation 1, add to 1/2 equation 3, add to equation 2 to get the equation you want. K for that reaction is
(sqrt k1) x (sqrt k3) x k2