Here is the height, in inches, of 10 randomly selected members of the girls' dance team and 10 randomly selected of the girls' volleyball team
Based on the interquartile ranges of the two sets of data, which is a reasonable conclusion concerning heights of the players on the two teams?
Volley ball team:67,63,70,67,68,69.70,68,72,68
Dance team:62,67,59,63,67,60,66,60,66,63
A. there is a greater variability of heights for the middle 50% of the dance team than for the middle50% of the volleyball team members
B. There is a greater variability of heights for the middle 50% of the volleyball team than for the middle50% of the dance team members
c. The variability for the 50% was the same for both team members
D. the average height, in inches, was higher for the members of the dance than for the members of the volleyball team.
I had B. since 68 is the middle and the is 5 numbers before it to get to the lowest number,63, and 4 to get to the highest number,72.
In dance 63, 59 is the lowest nuber, being 4 away and the highest is 67, being 4 away., so volleyball team has more variability.
Is this correct. I don't know if I did this correctly, can you help me; thanks
can you help with the above question
NEED ANSWERS FOR Quick Check Histograms Main Lesson Content.
Lesson 5
B C C D A I GOT 100% THERE YOU GO
To determine the interquartile range for each team, you need to first find the first quartile (Q1) and the third quartile (Q3) for each dataset. The interquartile range (IQR) is then calculated as the difference between Q3 and Q1.
For the volleyball team:
- Sort the data in ascending order: 63, 67, 68, 68, 69, 70, 70, 72.
- Find the median (Q2): 68.
- Find Q1: The median of the lower half of the data (63, 67, 68) is 67.
- Find Q3: The median of the upper half of the data (68, 69, 70, 70, 72) is 70.
- Calculate the IQR: Q3 - Q1 = 70 - 67 = 3.
For the dance team:
- Sort the data in ascending order: 59, 60, 60, 62, 63, 63, 66, 66, 67, 67.
- Find the median (Q2): 63.
- Find Q1: The median of the lower half of the data (59, 60, 60, 62, 63) is 60.
- Find Q3: The median of the upper half of the data (63, 66, 66, 67, 67) is 66.
- Calculate the IQR: Q3 - Q1 = 66 - 60 = 6.
Based on the interquartile ranges of the two sets of data, the correct answer is:
A. There is a greater variability of heights for the middle 50% of the dance team than for the middle 50% of the volleyball team members.
Your reasoning is correct. The IQR for the volleyball team is 3, while the IQR for the dance team is 6. This means that there is more variability in the heights of the dance team members compared to the volleyball team members within the middle 50% of their respective datasets.