Posted by **sheryl** on Sunday, March 31, 2013 at 12:31am.

Gary has 10 coins in his pocket.

2 quarters

5 dimes

3 nickels

without looking, Gary pulls 1 coin from

his pocket and puts it on a table. Then,

he pulls one more coin from his pocket.

What is the probability that the first

coin is a dime and the second coin is a

nickle?

- math -
**Khaled**, Sunday, March 31, 2013 at 5:48am
At the beginning, he had 10 coins and drew one. For this one to be a dime, it has a probability of 5/10 (5 dimes out of 10 coins in total).

So p1=1/2

Then, after drawing that coin, he has 9 total coins in his pocket, then he drew one. For this coin to be a nickle, it has a probability of 3/9 (3 nickels out of 9 total coins).

So p2=1/3

Thus, p=p1*p2=(1/2)*(1/3)

Therefore, p=1/6

- math -
**Nigel**, Tuesday, March 24, 2015 at 10:59am
5/10=1/2

3/9=1/3

1/2*1/3=1/6✌️

- math -
**BOLAJI Oretan**, Saturday, November 28, 2015 at 6:30am
Pro(dime) = 5/10

Without replacement total left= 9

Thus prob(nickel) = 3/9

Therefore

Pro(dime&nickel)=(5/10)(3/9)= 1/6

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