53 baskets were scored at the game. Jimmy scored 5 less than Trent. Trent and Justin scored the same amount. Evan scored ten more baskets than Trent. How many baskets did each boy get? Use algebra.
please help, thanx:)
Let T = the number scored by Trent and Justin.
T - 5 + 2T + T + 10 = 53
4T + 5 = 53
4T = 48
T = 12
thanks :)
You're welcome.
To solve this problem using algebra, let's assign variables to represent the number of baskets each boy scored.
Let's say Trent scored x baskets.
According to the information given, Jimmy scored 5 less than Trent. So Jimmy's baskets can be represented as (x - 5).
It is also mentioned that Trent and Justin scored the same amount. So Justin's baskets can also be represented as x.
Lastly, Evan scored ten more baskets than Trent. Therefore, Evan's baskets can be represented as (x + 10).
Now, we can add up the number of baskets each boy scored:
Trent (x) + Jimmy (x - 5) + Justin (x) + Evan (x + 10) equals the total number of baskets, which is 53:
x + (x - 5) + x + (x + 10) = 53
Simplifying the equation, we have:
4x + 5 = 53
Subtracting 5 on both sides of the equation:
4x = 48
Dividing both sides of the equation by 4:
x = 12
So, Trent scored 12 baskets.
Now we can substitute this value back into the expressions for the other boys:
Jimmy = x - 5 = 12 - 5 = 7
Justin = x = 12
Evan = x + 10 = 12 + 10 = 22
Therefore, Trent scored 12 baskets, Jimmy scored 7 baskets, Justin scored 12 baskets, and Evan scored 22 baskets.