Posted by **Iliana** on Saturday, March 30, 2013 at 12:47pm.

y' and y'' for x^2- xy + y^2 = 3

y'= (y-2x)/(2y-x)

y'' = [(y'-2)(2y-x)] - [(2yy' - x)(y- 2x)]/ ((2x-y)^2)

final answer for second derivative is:

[2y^2- 5xy + 2x^2 - 2y^3 + 8xy^2 - 8x^2y/ ((2x-y)^3)] - [(4y + 2x + xy - 2x^2)/((2y-x)^2)]

is this right. thank you

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