Posted by **Iliana** on Saturday, March 30, 2013 at 12:47pm.

y' and y'' for x^2- xy + y^2 = 3

y'= (y-2x)/(2y-x)

y'' = [(y'-2)(2y-x)] - [(2yy' - x)(y- 2x)]/ ((2x-y)^2)

final answer for second derivative is:

[2y^2- 5xy + 2x^2 - 2y^3 + 8xy^2 - 8x^2y/ ((2x-y)^3)] - [(4y + 2x + xy - 2x^2)/((2y-x)^2)]

is this right. thank you

## Answer This Question

## Related Questions

- AP Calculus - Find an equation of all tangent lines for the curve x^2-xy+y^2=16 ...
- College Calculus 1 - We have to find the first and second derivative of f(x)=x^(...
- Calculus AB - I'm trying to find the second derivative of h(x)= x^2 + cos(kx) My...
- calculus - Find the first and second derivative - simplify your answer. y=x/4x+1...
- calculus - Please help with this. I need the first derivative of f(x)=4(x+...
- calculus - Please help with this. I submitted it below but no one responded. I ...
- Calculus (Help) - Also I would like to know how to set this problem up in ...
- Calculus - I need to find the second derivative of y=x(x-1)^1/2. I found the ...
- Calculus - R=M^2(c/2-m/3) dR/dM=CM-M^2 I found the derivative. Now how would I ...
- Calculus--> bobpursley - How do you get m=0? from taking the second ...

More Related Questions