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December 20, 2014

December 20, 2014

Posted by **Modulus Function** on Saturday, March 30, 2013 at 11:01am.

I don't know how to sketch the graphs :(

- math -
**Reiny**, Saturday, March 30, 2013 at 11:32amin your previous post I showed you how to graph the absolute value of linear function.

The same concept is true for the above quadratics

for y=|(x-1)(x-3)|

You will have two parabolas, one is

y = (x-1)(x-3) the other is y = -(x-1)(x-3)

one will open up , the other will open down

They both have the same x-intercepts of 1 and 3

So sketch both of them, then erase the part of both of them that lies below the x-axis.

Do the same for the second equation.

They will have similar shapes, except the second has x-intercepts of 2 and -2

- math -
**Anonymous**, Saturday, March 30, 2013 at 11:50ami still don't really understand. How can i sketch y=(x-1)(x-3) and y=-(x-1)(x-3) ? what is the coordinate?

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