Posted by Anonymous on .
In how many ways can the letters of MAHABHARAT be arranged so that
i) B n T are never together
ii) M,A,T n H occurs at first four places
10 letters with 4 A's , 2 H's
a) without any restrictions, number of arrangements
= 10!/(4!2!) = 75600
consider the BT as one element
so we have 9 to arrange, with 4 A's and 2 H's
= 9!/(4!2!) = 7560
number of ways with the BT apart = 75600-7560 = 68040
b) Put the MATH in the front, that leaves
6 letters to arrange, containing of 3 A's
the remaining 6 letters can be arranged in 6!/3! or 120 ways.
That answer assumes that the front MATH stays that way.
If the MATH can be further arranged, but those letters still at the front,
then the number of ways would be 4!x(120) = 2880
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