Thursday

October 30, 2014

October 30, 2014

Posted by **Anonymous** on Saturday, March 30, 2013 at 12:47am.

i) B n T are never together

ii) M,A,T n H occurs at first four places

- mathematics -
**Reiny**, Saturday, March 30, 2013 at 8:12am10 letters with 4 A's , 2 H's

a) without any restrictions, number of arrangements

= 10!/(4!2!) = 75600

consider the BT as one element

so we have 9 to arrange, with 4 A's and 2 H's

= 9!/(4!2!) = 7560

number of ways with the BT apart = 75600-7560 = 68040

b) Put the MATH in the front, that leaves

6 letters to arrange, containing of 3 A's

the remaining 6 letters can be arranged in 6!/3! or 120 ways.

That answer assumes that the front MATH stays that way.

If the MATH can be further arranged, but those letters still at the front,

then the number of ways would be 4!x(120) = 2880

- mathematics -
**Gautom**, Friday, August 23, 2013 at 4:17amThe scale of a map is given as 1:2,00000. Two cities are 3 cm apart on the map. Calculate the actual distance between them.

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