Posted by Anonymous on Saturday, March 30, 2013 at 12:47am.
In how many ways can the letters of MAHABHARAT be arranged so that
i) B n T are never together
ii) M,A,T n H occurs at first four places

mathematics  Reiny, Saturday, March 30, 2013 at 8:12am
10 letters with 4 A's , 2 H's
a) without any restrictions, number of arrangements
= 10!/(4!2!) = 75600
consider the BT as one element
so we have 9 to arrange, with 4 A's and 2 H's
= 9!/(4!2!) = 7560
number of ways with the BT apart = 756007560 = 68040
b) Put the MATH in the front, that leaves
6 letters to arrange, containing of 3 A's
the remaining 6 letters can be arranged in 6!/3! or 120 ways.
That answer assumes that the front MATH stays that way.
If the MATH can be further arranged, but those letters still at the front,
then the number of ways would be 4!x(120) = 2880

mathematics  Gautom, Friday, August 23, 2013 at 4:17am
The scale of a map is given as 1:2,00000. Two cities are 3 cm apart on the map. Calculate the actual distance between them.
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