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March 26, 2017

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lowest+freezing+point+of+Kbr+AlNO33+CH3COONa+NaNO2+MgCl2+of+same+molality

  • chemistry - ,

    You would do well to make your post easier to read and understand.
    All you need is
    delta T = i*Kf*m
    i = 2 for KBr.
    i = 4 for Al(NO3)3
    i = 2 for CH3COONa
    i = 2 for NaNO2
    i = 3 for MgCl2
    If m is constant and Kf is constant, then delta T = some constant x i so the one with the most particles will have the lowest freezing point.

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