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A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

  • chemistry -

    mols glucose = grams/molar mass.
    Sole for mols.

    molality = m = mols/kg solvent.
    Solve for m.

    delta T = Kf*m
    Solve for delta T. That's the freezing point depression.

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