Wednesday

February 10, 2016
Posted by **tuhituhi** on Friday, March 29, 2013 at 4:20am.

- maths -
**Bosnian**, Friday, March 29, 2013 at 5:34am( 2 ^ n + 2 ^ ( n - 1 ) ) / ( 2 ^ ( n + 1 ) - 2 ^ n ) Multiply both sides by ( 2 ^ ( n + 1 ) - 2 ^ n )

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( 2 ^ n ) * 2 ^ ( n + 1 ) = 2 ^ ( 2 n + 1 )

2 ^ ( n - 1 ) * (2 ^ ( n + 1 ) ) = 2 ^ 2 n

2 ^ ( 2 n + 1 ) + 2 ^ 2 n = 3 * 4 ^ n

2 ^ ( 2 n ) * 2 ^ ( 2 n ) = ( 2 ^ ( 2 n ) ) ^ 2 = 2 ^ ( 4 n )

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( 2 ^ n + 2 ^ ( n - 1 ) ) / ( 2 ^ ( n + 1 ) - 2 ^ n ) =

2 ^ ( 2 n + 1 ) + 2 ^ 2 n / ( 2 ^ ( 2 n ) ) ^ 2 =

3 * 4 ^ n / ( 2 * 4 ^ n ) = 3 / 2