Wednesday

April 1, 2015

April 1, 2015

Posted by **Ian** on Thursday, March 28, 2013 at 10:58pm.

∣10(x+1)/(x^2+2x+3)∣≥1?

- Maths -
**Steve**, Friday, March 29, 2013 at 2:17pmsince x^2+2x+3 is always positive,

|10(x+1)| >= (x^2+2x+3)

Now, x+1 is either positive or negative

If x+1 is positive, |x+1| = x+1, and

10(x+1) >= x^2+2x+3

4-√23 <= x <= 4+√23

-.8 <= x <= 8.8

We started with x+1>=0, so every integer between -.8 and 8.8 works. There are 9 of them

If x+1 < 0, |x+1| = -(x+1) and we have

-10(x+1) >= x^2+2x+3

-6-√23 <= x <= -6+√23

-10.8 <= x <= -1.2

We started with x+1 < 0, so x < -1, and every integer between -10.8 and -1.2 works. There are 9 of those.

So, there are 18 integers that satisfy the inequality.

**Answer this Question**

**Related Questions**

science - 1 A ……... is a rectangular array of numbers that are ...

Maths - We have 15 points {Ai} placed within the unit sphere. What is the ...

MATHS - Find the largest possible integer n such that there exists a non-...

Maths - Find the number of pairs of non-negative integers (n,m), such that 1&#...

algebra - Find the largest possible integer n such that there exists a non-...

Probability - Let T1,T2,…,Tn be i.i.d. observations, each drawn from a common ...

probability - Let K be a discrete random variable with PMF pK(k)=⎧⎩...

probability - This figure below describes the joint PDF of the random variables ...

Probability - This figure below describes the joint PDF of the random variables ...

Mathematics - Find the number of pairs of non-negative integers (n,m), such that...