A rectangle's length is twice its width and it's perimeter is 48m. Find the dimensions.

P = 2L + 2W

48 = 2(2W) + 2W

48 = 6W

8 = W

2 * 8 = L

To find the dimensions of the rectangle, we can use the given information that the rectangle's length is twice its width and its perimeter is 48m.

Let's assign variables to the dimensions of the rectangle. Let's say the width is represented by 'w' meters. Since the length is twice the width, we can say the length is 2w meters.

To calculate the perimeter of the rectangle, we add all four sides together:

Perimeter = 2(length) + 2(width)

Substituting the given values into the equation:
48 = 2(2w) + 2(w)

Distributing and simplifying:
48 = 4w + 2w

Combining like terms:
48 = 6w

To solve for 'w', divide both sides of the equation by 6:
48/6 = w
8 = w

Therefore, the width of the rectangle is 8 meters.

To find the length, we can substitute the value of the width back into the equation for the length:
Length = 2w
Length = 2(8)
Length = 16

Therefore, the dimensions of the rectangle are 16 meters in length and 8 meters in width.