What is the molarity (moles per liter) of an aqueous solution that is prepared by dissolving 5.58g NaOH (MW=40) in enough water to make 250mL of solution?
How many mols NaOH do you have? That's mols = grams/molar mass.
Then M = mols/L solution.
Thank you..
I get
5.58g NaOH / 40g NaOH / 0.25L = 0.558 NaOH solution
To find the molarity (moles per liter) of the aqueous solution, you need to first determine the number of moles of NaOH in the 5.58 g of the compound.
Step 1: Calculate the number of moles of NaOH using the formula:
moles = mass / molar mass
The molar mass of NaOH is 40 g/mol:
moles = 5.58 g / 40 g/mol
Step 2: Convert the volume of the solution from mL to L:
250 mL = 250 / 1000 = 0.250 L
Step 3: Calculate the molarity using the formula:
Molarity (M) = moles / volume (in liters)
Molarity = moles / L
Molarity = (5.58 g / 40 g/mol) / 0.250 L
Therefore, the molarity of the aqueous solution prepared by dissolving 5.58 g NaOH in enough water to make 250 mL of solution is:
Molarity = (5.58 / 40) / 0.250
Molarity = 0.6985 mol/L or approximately 0.70 mol/L