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May 1, 2016
Posted by **Ira** on Thursday, March 28, 2013 at 5:08pm.

- Finite Math -
**Reiny**, Thursday, March 28, 2013 at 8:58pmnumber of ways without restriction = C(14,5) = 2002

What we CAN'T have is no fiction or all 5 fiction

number of ways no fiction = (6,0)xC(8,5) = 56

number of ways all fiction - C(6,5)xC(8,0) = 6

no of ways of your event = 2002 - 56 - 6 = 1940

The longer way would be to find

1F, 4NF = C(6,1) x C(8,4) = 420

2F , 3NF = C(6,2) x C(8,3) = 840

3F , 2NF = C(6,3) x C(8,2) = 560

4F, 1NF = C(6,4) x C(8,1) = 120

total = 1940