Product of Roots of Sums of Products of Difference
posted by please help me out!! on .
What is the product of all roots to the equation
If p(x) = an x^n + ...+a0,
p(x) = an (x-r1)(x-r2)....(x-rn)
where the rj are the roots of p(x). The product of all the roots is then related to p(0). Puting x = 0 in the above identity gives:
p(0) = (-1)^n an Product from j = 1 to n of rj
In your case, n = 6 and a6 = 2.