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Posted by on Thursday, March 28, 2013 at 11:38am.

Titration of 0.6500g of an acid requires 182.42 mL of 6.020x10^-3 N NaOH to reach the endpoint. What is the mass of an equivalent of this acid?

  • Chemistry - , Thursday, March 28, 2013 at 12:18pm

    A mighty weak acid to be used for titration in my opinion.
    mL x N x milliequivalent weight = grams.
    You want to find the mew, then multiply by 1000 for equivalent weight.

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