Posted by Mo on Thursday, March 28, 2013 at 11:19am.
the sum of 5 consecutive whole numbers is 2005. what is the sum of all the digits of these 5 numbers

Math  saiko, Thursday, March 28, 2013 at 11:23am
so you have,
(n2)+(n1)+n+(n+1)+(n+2)=2005
5n=2005
n=401
nos are,
399,400,401,402,403

Math  Damon, Thursday, March 28, 2013 at 11:25am
n4 + n2 + n + n+2 + n+4 = 2005
5 n = 2005
n = 401
so the list
397
399
401
403
405
so
2*3 + 3*4 + 2*9 + 25
= 61

Sorry  Damon, Thursday, March 28, 2013 at 11:26am
I misread it, thought it said ODD numbers
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