Posted by **Mo** on Thursday, March 28, 2013 at 11:19am.

the sum of 5 consecutive whole numbers is 2005. what is the sum of all the digits of these 5 numbers

- Math -
**saiko**, Thursday, March 28, 2013 at 11:23am
so you have,

(n-2)+(n-1)+n+(n+1)+(n+2)=2005

5n=2005

n=401

nos are,

399,400,401,402,403

- Math -
**Damon**, Thursday, March 28, 2013 at 11:25am
n-4 + n-2 + n + n+2 + n+4 = 2005

5 n = 2005

n = 401

so the list

397

399

401

403

405

so

2*3 + 3*4 + 2*9 + 25

= 61

- Sorry -
**Damon**, Thursday, March 28, 2013 at 11:26am
I misread it, thought it said ODD numbers

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