Pure water has a density of 1.00 g/ml at 297 . Calculate the molar concentration of pure water at this temperature. Would i just convert grams to moles, and ml to liters?
Yes. 1000 mL = 1000 g.
1000g/18.015 = ? mols and that is in 1 L so that is the M.
Ah, water, the H2Ombre of all liquids! You're absolutely right! To calculate the molar concentration of pure water, you can convert grams to moles and ml to liters.
First, you'll need to convert grams to moles. The molar mass of water (H2O) is approximately 18.015 g/mol. So if you have 1.00 g of water, you would have:
1.00 g / (18.015 g/mol) = 0.0555 mol (approximately)
Next, you'll need to convert ml to liters. Since there are 1000 ml in a liter, if you have 1.00 ml, you would have:
1.00 ml / 1000 = 0.001 L
Now you can calculate the molar concentration by dividing the number of moles by the volume in liters:
0.0555 mol / 0.001 L = 55.5 mol/L
Therefore, the molar concentration of pure water at 297 Kelvin would be approximately 55.5 mol/L. That's one well-concentrated water molecule party!
Yes, to calculate the molar concentration of pure water at a given temperature, you would indeed convert grams to moles and ml to liters. Here's how you can do it step-by-step:
1. Convert the density from grams per milliliter to grams per liter. Since there are 1000 milliliters in a liter, multiply the given density by 1000:
1.00 g/mL x 1000 mL/L = 1000 g/L
2. Convert grams of water to moles. The molar mass of water (H2O) is approximately 18.015 g/mol, so divide the mass of water by the molar mass:
1000 g/L ÷ 18.015 g/mol ≈ 55.50 mol/L
3. The molar concentration is given in moles per liter (mol/L), so the molar concentration of pure water at 297 K is approximately 55.50 mol/L.
It is worth noting that this calculation assumes that at 297 K, pure water behaves ideally and does not contain any dissolved substances that would affect its density or molar concentration.
To calculate the molar concentration of pure water at a given temperature, you will indeed need to convert grams to moles and milliliters to liters. The molar concentration, usually denoted as M or mol/L, represents the number of moles of solute per liter of solution.
To convert grams of water to moles, you will need to use the molar mass of water, which is approximately 18.015 g/mol. The molar mass of water can be obtained by adding the atomic masses of hydrogen (1.00784 g/mol) and oxygen (15.999 g/mol).
Similarly, to convert milliliters to liters, you need to divide the given volume by 1000.
Let's go through the calculation:
1. Convert grams to moles:
Given mass of water = 1.00 g
Molar mass of water = 18.015 g/mol
Moles of water = (Given mass of water) / (Molar mass of water)
Moles of water = 1.00 g / 18.015 g/mol
2. Convert milliliters to liters:
Given volume of water = 1.00 mL
Volume of water in liters = (Given volume of water) / 1000
Volume of water in liters = 1.00 mL / 1000
Now that you have the moles of water and the volume of water in liters, you can calculate the molar concentration using the formula:
Molar concentration of water = (Moles of water) / (Volume of water in liters)
Substitute the values into the formula to get the final answer.
Note: The temperature given in your question (297) is incomplete. The unit of temperature is missing, so it is not possible to calculate an accurate molar concentration without knowing the temperature (e.g., in Celsius or Kelvin).