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April 1, 2015

April 1, 2015

Posted by **Alley** on Thursday, March 28, 2013 at 9:05am.

8x-3 ≥ -3x^2

- Solve the inequality -
**Reiny**, Thursday, March 28, 2013 at 9:27am8x-3 ≥ -3x^2

3x^2 + 8x - 3 ≥ 0

(x + 3)(3x - 1) ≥ 0

critical values are x = -3 and x = 1/3

visualize the parabola y = 3x^2 + 8x - 3

it would have x-intercepts of -3 and 1/3 and be above the x-axis , y≥0 , for x ≤ -3 or x ≥ 1/3

so :

x ≤ -3 or x ≥ 1/3

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