Thursday

April 2, 2015

April 2, 2015

Posted by **Kris** on Thursday, March 28, 2013 at 7:38am.

1. Solve the system by triangularizing the augmented matrix and using back substitution. If the system is linearly dependent, give the solution in terms of a parameter.

-3x+y-z=-4

6x-2y+2z=8

-12x+4y-4z=-16

2. Solve the system by triangularizing the augmented matrix and using back substitution.

6x=y-4

3y=-13-7x

3. What row operation would produce zero beneath the first entry in the diagonal?

1 2 | -1

8 -2 | -2

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