Posted by Chuck on .
A swimming pool, 20.0 m 12.5 m, is filled with water to a depth of 3.73 m. If the initial temperature of the water is 18.5°C, how much heat must be added to the water to raise its temperature to 28.5°C? Assume that the density of water is 1.000 g/mL.
I would change the dimensions to cm, then h x w x l = volume in cc.
That many cc will be that many grams H2O.
Then q = mass H2O in grams x specific heat H2O in J/g (or cal/g) x (Tfinal-Tinitial).