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February 1, 2015

February 1, 2015

Posted by **Kristen** on Wednesday, March 27, 2013 at 9:36pm.

1.) Solve the system by triangularizing the augmented matrix and using back substitution.

0.09x-0.15y+0.39

-0.18x+0.35y=-0.88

2.) Solve the system by triangularizing the augmented matrix and using back substitution.

-x-y+z=1

x-y-4z=-7

4x+y+z=6

3.) Perform the indicated row operation, then write the new matrix.

-4 4 | 4

9 -6 | 5 -2R1+ R2 ---> R2

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