Posted by **Amber** on Wednesday, March 27, 2013 at 7:40pm.

Consider the differential equation given by dy/dx=(xy)/(2)

A) sketch a slope field (I already did this)

B) let f be the function that satisfies the given fifferential equation for the tangent line to the curve y=f(x) through the point (1,1). Then use your tangent line equation to estimate the value of f(1.2).

C) find the particular solution y=f(x) to the differential equation with the initial condition f(1)=1. Use your solution to find f(1.2).

D) compare your estimate of f(1.2) found in part b to the actual value of f(1.2)

E) was the estimate under or over? Use the slope field to explain why?

- I would like to understand my calc homework:/ -
**Writeacher**, Wednesday, March 27, 2013 at 7:41pm
You need to have patience and not post the same stuff umpteen times. The tutors who concentrate on this type of math are not online yet.

- I would like to understand my calc homework:/ -
**Ms. Sue**, Wednesday, March 27, 2013 at 7:41pm
Please do not keep posting the same question over and over. It's considered spamming and could get you banned from posting here.

- I would like to understand my calc homework:/ -
**Damon**, Wednesday, March 27, 2013 at 7:56pm
B)

at (1 , 1) dy/dx = slope = 1*1/2 = .5

so

y = .5 x + b is tangent for some b

put in (1 , 1 )

1 = .5 + b

b = .5

so tangent at (1,1) is

y = .5 x + .5

at x = 1.2

y = .5(1.2) + .5 = 1.1

==========================

C)

dy/y = (1/2) x dx

ln y = (1/4) x^2 + C

y = k e^(x^2/4)

1 = k e^(1/4)

1 = 1.28 k

k = .779

y = .779 e^(x^2/4)

at x = 1.2

y = .779 e^(1.44/4)

y = .779 * 1.433

y = 1.116

etc

- I would like to understand my calc homework:/ -
**Damon**, Wednesday, March 27, 2013 at 7:59pm
Do not panic. Plug and chug.

- I would like to understand my calc homework:/ -
**Amber**, Wednesday, March 27, 2013 at 8:18pm
I think the whole non panicing ship sailed a long time ago haha. Sorry and thanks for the help!

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