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March 29, 2015

March 29, 2015

Posted by **Anonymous** on Wednesday, March 27, 2013 at 11:58am.

- Algebra -
**Steve**, Wednesday, March 27, 2013 at 12:24pmd = √(4+(y-5)^2) + √(9+(y-9)^2)

dd/dy = (y-5)/√(4+(y-5)^2) + (y-9)/√(9+(y-9)^2)

= [(y-9)√(4+(y-5)^2) + (y-5)√(9+(y-9)^2)]/(√(4+(y-5)^2) * √(9+(y-9)^2))

dd/dy=0 when

(y-9)√(4+(y-5)^2) + (y-5)√(9+(y-9)^2) = 0

y = 33/5

a+b=38

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