1. The lift force is mass*g if the aircraft is at constant speed downward gliding.
2. rate losing PE?
altitude= vertical speed*time=
rate of altitude loss= speedgiven*sinGlideAngle
rate of PE loss: mg*rateOfAltitudeLossAbove.
Lift does not act perpendicular to the wings but to the oncoming air flow. The two angles differ by the angle of attack.
speed = 129*10^3/3600 = 35.8 m/s
weight = 1250 * 9.81 = 12,263 N
Path at angle T down from Horizontal
weight down = 12,263 N
Lift component up = L cos T
Drag component up = 1300 sin T
12,263 = L cos T + 1300 sin T
weight not horizontal
Lift forward = L sin T
drag back = 1300 cos T
1300 cos T = L sin T
I agree with Damon, I was thinking the drag force as horizontal.
By the way, this means that for a glider:
Drag/Lift = tangent of steady glide angle
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