Two positive point charges are placed on the x-axis. One, of magnitude 4Q, is placed at the origin. The other, of magnitude Q is placed at x=3 m. Neither charge is able to move. Where on the x-axis in meters can I place a third positive point charge such that the magnitude of the net force on the third charge is zero?

To find the position on the x-axis where a third positive point charge will experience a net force of zero, we can use the concept of electrostatic equilibrium. In electrostatic equilibrium, the net force acting on a charge is zero.

Let's assume that the third positive point charge is placed at a position x meters on the x-axis. The force on the third charge due to the 4Q charge at the origin can be calculated using Coulomb's law:

F1 = k * (4Q * q) / r1^2

where F1 is the force on the third charge due to the 4Q charge, Q is the charge of the third charge, r1 is the distance between the third charge and the 4Q charge, and k is the electrostatic constant.

Similarly, the force on the third charge due to the Q charge at x = 3 m can be calculated as:

F2 = k * (Q * q) / r2^2

where F2 is the force on the third charge due to the Q charge, r2 is the distance between the third charge and the Q charge.

For the net force to be zero, we need F1 + F2 to equal zero:

F1 + F2 = 0

Simplifying the equation, we get:

k * (4Q * q) / r1^2 + k * (Q * q) / r2^2 = 0

To solve this equation, we substitute the values of r1 and r2:

r1 = x
r2 = 3 - x

Now, the equation becomes:

k * (4Q * q) / x^2 + k * (Q * q) / (3 - x)^2 = 0

To find the value of x that satisfies this equation, we can solve it algebraically or graphically.

The algebraic solution involves manipulating the equation and solving for x. However, since the equation is non-linear, it can be quite challenging to solve analytically. In this case, the graphical approach might be more convenient.

By plotting the left-hand side of the equation as a function of x and finding the x-coordinate(s) where the graph intersects the x-axis, we can find the solution(s) to the equation.

To summarize, you can find the position on the x-axis where a third positive point charge experiences zero net force by setting up the equation for the forces exerted by the other two charges and finding the values of x that satisfy the equation.