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September 30, 2014

September 30, 2014

Posted by **aria** on Wednesday, March 27, 2013 at 12:24am.

F9x)=x^3-5x^2+4x-20; zero:2i

I don't get it. Can someone please show me what to do with this?

- math -
**Steve**, Wednesday, March 27, 2013 at 10:47amif 2i is a zero, so is -2i

so, (x-2i)(x+2i) = x^2+4 divides f(x)

doing the division, we have

f(x) = (x-5)(x^2+4)

so, the zeros are 5,2i,-2i

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