Posted by Austin on Tuesday, March 26, 2013 at 11:35pm.
How many integers satisfy the inequality
\left \frac { 10(x+1) } {x^2 + 2x + 3 } \right \geq 1?

math  Steve, Wednesday, March 27, 2013 at 11:08am
10(x+1)/(x^2+2x+3) >= 1
since x^2+2x+3 > 0,
10x+10 >= x^2+2x+3
x^2  8x  7 <= 0
So, all integers n such that
4√23 <= n <= 4+√23