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August 30, 2014

August 30, 2014

Posted by **Austin** on Tuesday, March 26, 2013 at 11:35pm.

\left| \frac { 10(x+1) } {x^2 + 2x + 3 } \right| \geq 1?

- math -
**Steve**, Wednesday, March 27, 2013 at 11:08am10(x+1)/(x^2+2x+3) >= 1

since x^2+2x+3 > 0,

10x+10 >= x^2+2x+3

x^2 - 8x - 7 <= 0

So, all integers n such that

4-√23 <= n <= 4+√23

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