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September 30, 2014

September 30, 2014

Posted by **asia** on Tuesday, March 26, 2013 at 11:35pm.

f(x)=3x^2+x-4/2x^2-5x

a. determine the symmetry of the function.

b. find the x and y intercepts.

c. find the verticle asymptote

d.find the horizontal asymptote

e.plot the points between and beyond the x intercept and verticle asymptote.

I don't get any of this. help me please?

- pre calculus -
**Steve**, Wednesday, March 27, 2013 at 11:17amHow can you not get

**any**of this?

symmetry may be a bit tough:

f(x) = (3x+4)(x-1) / x(2x-5)

I don't see any symmetry there at all.

the intercepts are easy, right?

Vertical asymptote where denominator si zero

horizontal asymptote is y when x gets huge. There, all the small powers of x become insignificant, and you are working with

3x^2/2x^2 = 3/2

visit wolframalpha.com and enter

(3x^2+x-4)/(2x^2-5x)

for a graph

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