Posted by Joshua on .
A brick is thrown off a building at a 25 degree angle at 10m/s, it lands 40 meters away, How high is the building?
Time of flight = t = (40 m)/(Vo*cos25)
= 4.41 s
since the horizontal velocity component is constant.
Vo*sin25*t - (1/2)gt^2 = -(Height)
since the vertical location is
-(Height) when it hits the ground
Height = 4.9 t^2 - 4.226 t
= 95.3 - 18.6 = 76.7 m