Tuesday

March 3, 2015

March 3, 2015

Posted by **suzy** on Tuesday, March 26, 2013 at 9:01pm.

How would I solve

- algerba -
**bobpursley**, Tuesday, March 26, 2013 at 9:10pm2k^2+4k-10=0

k^2+2k-5=0

use the quadratic equation:

k= (-2+-sqrt(4+20))/2= -1+-sqrt6

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