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October 25, 2014

October 25, 2014

Posted by **Mary** on Tuesday, March 26, 2013 at 2:47pm.

dy/dx for y = sec(tan x)

I have the answer, but I have no idea how to get there. I know that the derivative of sec x = sec x tan x and that the derivative of tan x is sec^2 x. But sec doesn't have an x, so ...?

- Calculus 1A -
**Steve**, Tuesday, March 26, 2013 at 2:57pmd/dx secu = secu tanu du/dx, so

y' = sec(tanx) tan(tanx) sec^2(x)

- Calculus 1A -
**Mary**, Tuesday, March 26, 2013 at 3:14pmthanks!!!!!!

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