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March 30, 2017

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Enough of a monoprotic acid is dissolved in water to produce a 0.0190 M solution. The pH of the resulting solution is 2.33. Calculate the Ka for the acid.

  • Chemistry - ,

    pH = -log (H^+)
    2.33 = -log(H^+)
    (H^+) = about 0.005 which is only an estimate.
    ..........HA ==> H^+ + A^-
    I......0.0190....0......0
    C.......-x.......x......x
    E...0.0190-x.....x......x

    Ka = (H^+)(A^-)/(HA)
    You know the value of x, substitute those values into the Ka expression and solve for Ka.

  • Chemistry - ,

    I know how to do the ice chart and set up i just don't know how to get the x value that you are saying that i know...

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