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January 29, 2015

January 29, 2015

Posted by **Ashley** on Tuesday, March 26, 2013 at 12:44pm.

f(x)=4x^3+6x^2-7x+1; [-4,-2]

f(-4)=

- Use the intermediate value -
**Steve**, Tuesday, March 26, 2013 at 3:33pmf(-4) = -131

f(-2) = 7

IVT says that f(x) assumes every value between -131 and 7 on [-4,-2]. In particular, there is some c in [-4,-2] where f(x) = 0.

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