Physics
posted by Renay on .
A test rocket is launched vertically from ground level (y=0m), at time t=0.0 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 97 m and acquired a velocity of 40 m/s. The rocket continues to rise in upward flight, reaches maximum height, and falls back to the ground. What is the upward acceleration of the rocket during the burn phase?

Assuming constant acceleration:
use the kinematic equation Vf^2=Vo^2+2ad
there is no Vo, so the equation becomes: Vf^2=2ad
substitute and you get: 40^2=2a(97)
solve for a: a= 8.25 m/s or 8.3 m/s if you use sig. figs.
Hope this helps! 
21

rw