Posted by mazandie Magaduzela on Tuesday, March 26, 2013 at 12:28pm.
how can i find a general solution of g(x)when they give me g(X) =cos (x+30)and g(X)= 2sinx

maths  Steve, Tuesday, March 26, 2013 at 12:34pm
well, when does
cos(x+30) = 2sinx
√3/2 cosx  1/2 sinx = 2sinx
√3/2 cosx = 3/2 sinx
tanx = 1/√3
since tan30 = 1/√3,
x = (18030) or (36030) = 150 or 330
or, more generally,
x = 180n30 for any integer n
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