Posted by mazandie Magaduzela on .
how can i find a general solution of g(x)when they give me g(X) =cos (x+30)and g(X)= 2sinx

maths 
Steve,
well, when does
cos(x+30) = 2sinx
√3/2 cosx  1/2 sinx = 2sinx
√3/2 cosx = 3/2 sinx
tanx = 1/√3
since tan30 = 1/√3,
x = (18030) or (36030) = 150 or 330
or, more generally,
x = 180n30 for any integer n