Posted by **visoth** on Tuesday, March 26, 2013 at 11:00am.

differentiate x(x-3)^2

do I product and chain rule?

- calculus 1 -
**bobpursley**, Tuesday, March 26, 2013 at 11:07am
f= uv

f'=uv'+vu'

f'= 1*(x-3)^2+ 2x(x-3)*1

- calculus 1 -
**visoth**, Tuesday, March 26, 2013 at 11:46am
shouldn't it be 1 * (x-3)^2 + 2x(x-3)^1 ? instead of 2x(x-3) * 1 at the end?

- calculus 1 -
**visoth**, Tuesday, March 26, 2013 at 12:02pm
oh wait nvm i see what i did wrong

- calculus 1 giyani high -
**gudlhuza**, Tuesday, March 26, 2013 at 1:45pm
x(x-3)^2

=x(x-3)(x-3)

=x(x^2-3x-3x+9)

=x^3-6x^2+9x

=3x^2-12x+9

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