Posted by visoth on Tuesday, March 26, 2013 at 11:00am.
differentiate x(x3)^2
do I product and chain rule?

calculus 1  bobpursley, Tuesday, March 26, 2013 at 11:07am
f= uv
f'=uv'+vu'
f'= 1*(x3)^2+ 2x(x3)*1

calculus 1  visoth, Tuesday, March 26, 2013 at 11:46am
shouldn't it be 1 * (x3)^2 + 2x(x3)^1 ? instead of 2x(x3) * 1 at the end?

calculus 1  visoth, Tuesday, March 26, 2013 at 12:02pm
oh wait nvm i see what i did wrong

calculus 1 giyani high  gudlhuza, Tuesday, March 26, 2013 at 1:45pm
x(x3)^2
=x(x3)(x3)
=x(x^23x3x+9)
=x^36x^2+9x
=3x^212x+9
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